q^2-26q+25=0

Solution for q^2-26q+25=0 equation:

Simplifying
q2 + -26q + 25 = 0

Reorder the terms:
25 + -26q + q2 = 0

Solving
25 + -26q + q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(1 + -1q)(25 + -1q) = 0

Subproblem 1
Set the factor '(1 + -1q)' equal to zero and attempt to solve:

Simplifying
1 + -1q = 0

Solving
1 + -1q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1q = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1q = 0 + -1
-1q = 0 + -1

Combine like terms: 0 + -1 = -1
-1q = -1

Divide each side by '-1'.
q = 1

Simplifying
q = 1
Subproblem 2
Set the factor '(25 + -1q)' equal to zero and attempt to solve:

Simplifying
25 + -1q = 0

Solving
25 + -1q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-25' to each side of the equation.
25 + -25 + -1q = 0 + -25

Combine like terms: 25 + -25 = 0
0 + -1q = 0 + -25
-1q = 0 + -25

Combine like terms: 0 + -25 = -25
-1q = -25

Divide each side by '-1'.
q = 25

Simplifying
q = 25
Solution
q = {1, 25}